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x^2-2.4x+0.48=0
a = 1; b = -2.4; c = +0.48;
Δ = b2-4ac
Δ = -2.42-4·1·0.48
Δ = 3.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{3.84}}{2*1}=\frac{2.4-\sqrt{3.84}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{3.84}}{2*1}=\frac{2.4+\sqrt{3.84}}{2} $
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